Segment WC
is tangent to circle O
at point W.
CO¯¯¯¯¯¯¯¯,
CW¯¯¯¯¯¯¯¯¯,
and OW¯¯¯¯¯¯¯¯¯
are drawn in to create △OWC.
Circle O as described, where O W equals r.If WC=15
and CO=17,
what is OW?
Enter the correct value.
Using the Pythagorean Theorem in triangle OWC, we have:
OW^2 + CW^2 = CO^2
Substitute the given values:
OW^2 + (15)^2 = (17)^2
OW^2 + 225 = 289
OW^2 = 289 - 225
OW^2 = 64
OW = √64
OW = 8
Therefore, the length of OW is 8.