A transformer has 700 turns on its secondary and 100 turns on its primary. The primary is connected to a 14-V source.
(a) What is the voltage output of the secondary?
____ V
(b) If 3 A flows in the primary coil, how much current is there in the secondary coil?
_____A
(a) Using the transformer voltage equation, we can calculate the voltage output of the secondary coil:
Vp/Vs = Np/Ns
where Vp = voltage on primary coil, Vs = voltage on secondary coil, Np = number of turns on primary coil, and Ns = number of turns on secondary coil.
Plugging in the values, we get:
14/Vs = 100/700
Vs = (700/100) x 14
Vs = 98 V
Therefore, the voltage output of the secondary coil is 98 V.
(b) Using the transformer current equation, we can calculate the current in the secondary coil:
Ip/Is = Ns/Np
where Ip = current in primary coil, Is = current in secondary coil, Ns = number of turns on secondary coil, and Np = number of turns on primary coil.
Plugging in the values, we get:
3/Is = 700/100
Is = (100/700) x 3
Is = 0.429 A
Therefore, the current in the secondary coil is 0.429 A.