A 4.00 W LED light bulb is turned on. It has an operating voltage of 120 V.
How much current (in A) flows through the bulb?
____ A
What is the resistance (in Ω) of the bulb?
____ Ω
How much energy (in J) is used each second?
_____J each second
To find the current flowing through the bulb, we can use Ohm's Law.
Current (I) = Power (P) / Voltage (V)
I = 4.00 W / 120 V
I = 0.033 A
Therefore, 0.033 A flows through the bulb.
To find the resistance of the bulb, we can use Ohm's Law again.
Resistance (R) = Voltage (V) / Current (I)
R = 120 V / 0.033 A
R = 3636.36 Ω
Therefore, the resistance of the bulb is 3636.36 Ω.
To find the energy used each second, we can use the formula:
Energy (E) = Power (P) * Time (t)
E = 4.00 W * 1 s
E = 4.00 J
Therefore, 4.00 J of energy is used each second.