What are the forces (in N) on two charges of +0.400 C and
−3.00
C, respectively, if they are separated by a distance of 4.00 m?
magnitude
N
attract or repel?
To calculate the force between the two charges, we can use Coulomb's Law:
F = k * |q1 * q2| / r^2
Where:
F = force between the charges
k = Coulomb's constant = 8.9875 x 10^9 N m^2/C^2
q1 = charge of the first charge = +0.400 C
q2 = charge of the second charge = -3.00 C
r = distance between the charges = 4.00 m
Plugging in the values, we get:
F = 8.9875 x 10^9 * |0.400 * (-3.00)| / 4^2
F = 1.347 x 10^9 N
Therefore, the magnitude of the force between the two charges is 1.347 x 10^9 N. The charges have different signs (+ and -), so they will attract each other.