Use the image to answer the question.
A horizontal rectangle is shown with two small right triangles extending above and below on the left side of the rectangle. The overall length of the horizontal rectangle is 8 feet, and the width is 4 feet. The two right triangles extend outward top and bottom from the left width side of the rectangle by 2 feet each. The sides of the triangles that are common to the length of the rectangle are labeled as 3 feet.
Mr. Ming’s second grade class is making a mural to celebrate the completion of their unit on astronomy. The image of the spaceship will be central to the mural. What is the area of the spaceship?
(1 point)
Responses
32 ft.2
32 ft. squared
35 ft.2
35 ft. squared
30 ft.2
30 ft. squared
38 ft.2
The area of the spaceship can be calculated by adding the area of the rectangle and the two triangles.
Area of rectangle: length x width = 8 ft x 4 ft = 32 ft²
Area of triangle: 1/2 x base x height = 1/2 x 4 ft x 2 ft = 4 ft² (for each triangle, total 8 ft²)
Total area of spaceship: 32 ft² (rectangle) + 8 ft² (triangles) = 40 ft²
So, the area of the spaceship is 40 ft².