A box of sugar needs to contain more than 60 in.3 . The height of the box is 8 inches. How would you write and solve an inequality describing b , the area of the base of the box?(1 point)
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height of the box = 8 inches
volume of the box > 60 cubic inches
Let's assume the base of the box is a square with side length b inches.
Then, the area of the base of the box would be b^2 in^2.
The volume of a rectangular prism (in this case, a box) is given by V = base area x height.
So, the volume of the box would be V = b^2 x 8 = 8b^2 in^3.
Given that the volume of the box is more than 60 in^3:
8b^2 > 60
b^2 > 60/8
b^2 > 7.5
Therefore, the inequality describing b, the area of the base of the box, would be:
b^2 > 7.5