jerry wants to wrap a present in a box for his mother. The box measures 10 cm wide. 4 cm high, and 17 cm long. How much wrapping paper will jerry need to wrap the present?
To calculate the amount of wrapping paper Jerry will need, we need to determine the surface area of the box.
The surface area of a rectangular box can be calculated by finding the area of each side and adding them all together.
The box has 6 sides:
1. Two sides that measure 10 cm by 4 cm = 10 cm x 4 cm = 40 cm²
2. Two sides that measure 4 cm by 17 cm = 4 cm x 17 cm = 68 cm²
3. Two sides that measure 10 cm by 17 cm = 10 cm x 17 cm = 170 cm²
Now, add up all the areas to get the total surface area:
40 cm² + 40 cm² + 68 cm² + 68 cm² + 170 cm² + 170 cm² = 546 cm²
Jerry will need 546 cm² of wrapping paper to wrap the present.
A toy came in a container that is shaped like a triangular prism. How much wrapping paper is needed to wrap the toy? Round your answer to the nearest whole number.
The sides of the triangular prism are 5.1 cm height 27.9 cm base 28.4 cm on the angled height
and 30.5 cm on the length
To calculate the amount of wrapping paper needed to wrap the triangular prism container, we first need to calculate the surface area of each face and then add them together.
1. Calculate the area of the two triangular faces:
- The formula for the area of a triangle is: 0.5 * base * height
Area of one triangular face = 0.5 * 27.9 cm * 5.1 cm = 71.145 cm²
Area of two triangular faces = 2 * 71.145 cm² = 142.29 cm²
2. Calculate the area of the three rectangular faces:
- The formula for the area of a rectangle is: length * width
Area of the rectangular face with dimensions 30.5 cm x 5.1 cm = 155.55 cm²
Area of the rectangular face with dimensions 30.5 cm x 28.4 cm = 865.2 cm²
Area of the rectangular face with dimensions 28.4 cm x 5.1 cm = 144.84 cm²
Add the areas of the three rectangular faces:
155.55 cm² + 865.2 cm² + 144.84 cm² = 1165.59 cm²
3. Add the areas of the two triangular faces and three rectangular faces:
142.29 cm² + 1165.59 cm² = 1307.88 cm²
Therefore, Jerry will need approximately 1308 cm² of wrapping paper to wrap the toy in the triangular prism container.