3x-4y=40
5x-5y=55
Solve the system of equations
To solve this system of equations, we can use the method of substitution or elimination.
Starting with the first equation, we can solve for x in terms of y:
3x - 4y = 40
3x = 40 + 4y
x = (40 + 4y) / 3
Now, substitute this expression for x into the second equation:
5((40 + 4y) / 3) - 5y = 55
(200 + 20y) / 3 - 5y = 55
200 + 20y - 15y = 165
5y = -35
y = -7
Now that we've found the value of y, we can substitute it back into the first equation to solve for x:
3x - 4(-7) = 40
3x + 28 = 40
3x = 12
x = 4
Therefore, the solution to the system of equations is x = 4 and y = -7.