What is the theoretical yield of SO3 produced by 6.16g of S?
The balanced chemical equation for the formation of SO3 from S is:
2S + 3O2 -> 2SO3
From the equation, we can see that the mole ratio of S to SO3 is 2:2 or 1:1.
First, we need to determine the number of moles of S:
1. Calculate the molar mass of S:
Molar mass of S = 32.06 g/mol
2. Calculate the number of moles of S:
moles of S = 6.16g / 32.06 g/mol ≈ 0.192 moles
Since the mole ratio of S to SO3 is 1:1, the number of moles of SO3 produced is also 0.192 moles.
Now, we can calculate the theoretical yield of SO3 by converting moles to grams:
1. Calculate the molar mass of SO3:
Molar mass of SO3 = 80.06 g/mol
2. Calculate the theoretical yield of SO3:
theoretical yield of SO3 = 0.192 moles SO3 * 80.06 g/mol ≈ 15.4 g
Therefore, the theoretical yield of SO3 produced by 6.16g of S is approximately 15.4 grams.