A tennis ball is dropped from a certain height. Its height in feet is given by h, equals, minus, 16, t, squared, plus, 36h=−16t
2
+36 where tt represents the time in seconds after launch. How long is the ball in the air?
To find out how long the ball is in the air, we need to find the time when the height (h) is equal to 0 (the point where the ball hits the ground).
Given the equation h = -16t^2 + 36, we can set h = 0 and solve for t:
0 = -16t^2 + 36
16t^2 = 36
t^2 = 36/16
t^2 = 2.25
t = sqrt(2.25)
t = 1.5
Therefore, the ball is in the air for 1.5 seconds.