Calculate the volume in milliliters of a 0.217 mol/L potassium permanganate solution that contains 25.0 g of potassium permanganate (KMnO4). Be sure your answer has the correct number of significant digits.
To calculate the volume of the solution, we can use the formula:
Volume = (mass of solute (g) / molar mass of solute (g/mol)) / concentration (mol/L)
First, let's find the molar mass of potassium permanganate (KMnO4):
K: 1 mol x 39.10 g/mol = 39.10 g/mol
Mn: 1 mol x 54.94 g/mol = 54.94 g/mol
O: 4 mol x 16.00 g/mol = 64.00 g/mol
Total molar mass = 39.10 + 54.94 + 64.00 = 158.04 g/mol
Now we can substitute the given values into the formula:
Volume = (25.0 g / 158.04 g/mol) / 0.217 mol/L
Volume = (0.1583 mol) / 0.217 mol/L
Volume = 0.7290 L
Lastly, we need to convert the volume from liters to milliliters:
Volume (mL) = 0.7290 L x 1000 mL/L = 729 mL
Therefore, the volume of the potassium permanganate solution is 729 mL.