Calculate the volume in milliliters of a 0.46M sodium carbonate solution that contains 25.0 g of sodium carbonate (Na2CO3). Be sure your answer h correct number of significant digits.
To calculate the volume of the solution, we first need to determine the number of moles of sodium carbonate in 25.0 g.
The molar mass of Na2CO3 is:
Na: 22.98977 g/mol * 2 = 45.97954 g/mol
C: 12.0107 g/mol
O: 15.9994 g/mol * 3 = 47.9982 g/mol
Total molar mass = 45.97954 + 12.0107 + 47.9982 = 105.98844 g/mol
Number of moles of Na2CO3 = 25.0 g / 105.98844 g/mol = 0.236 mols
Now, we can use the molarity formula to calculate the volume of the solution:
Molarity (M) = moles of solute / volume of solution (in liters)
0.46 M = 0.236 mol / volume (in liters)
Volume (in liters) = 0.236 mol / 0.46 mol/L = 0.513 L
Finally, we convert the volume to milliliters by multiplying by 1000:
Volume (in milliliters) = 0.513 L * 1000 mL/L = 513 mL
Therefore, the volume of the 0.46M sodium carbonate solution that contains 25.0 g of Na2CO3 is 513 milliliters.