A chemist prepares a solution of mercury (I) chloride (Hg2Cl2) by measuring out 0.44 mg of mercury(I) chloride into a 150. mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in mol/L of the chemist's mercuryI) chloride solution. Be sure your answer has the correct number of significant digits.
To calculate the concentration of the solution in mol/L, we first need to convert the mass of mercury(I) chloride from mg to grams.
0.44 mg of Hg2Cl2 = 0.44 x 10^-3 g = 4.4 x 10^-4 g
Next, we need to calculate the molar mass of Hg2Cl2.
2 atoms of Hg (200.59 g/mol) + 2 atoms of Cl (35.453 g/mol) = 471.092 g/mol
Now we can calculate the number of moles of Hg2Cl2 in the solution:
moles = mass / molar mass
moles = 4.4 x 10^-4 g / 471.092 g/mol = 9.3445 x 10^-7 mol
Finally, we can calculate the concentration in mol/L:
concentration (mol/L) = moles / volume (L)
concentration = 9.3445 x 10^-7 mol / 0.150 L = 6.23 x 10^-6 mol/L
Therefore, the concentration of the chemist's mercury(I) chloride solution is 6.23 x 10^-6 mol/L.