help me with this What is the molarity of an HCl solution if 10.5 mL of a 0.44 M NaOH solution are needed to neutralize 28.0 mL of the sample?
Part: 0 / 2
Part 1 of 2
Write the bala
nced chemical equation for the reaction between HCl and NaOH:
HCl + NaOH -> NaCl + H2O
Part 2 of 2
Calculate the number of moles of NaOH used in the reaction:
10.5 mL of 0.44 M NaOH solution is equal to 0.0105 L x 0.44 mol/L = 0.00462 moles of NaOH
Use the balanced chemical equation to determine the number of moles of HCl in the sample:
Since NaOH and HCl react in a 1:1 ratio, the number of moles of HCl is also 0.00462 moles.
Calculate the molarity of the HCl solution:
Molarity = moles of solute / volume of solution in liters
Molarity = 0.00462 moles / 0.028 L = 0.165 M
Therefore, the molarity of the HCl solution is 0.165 M.