can you help me with this
Calculate the value of
OH from the given
Note: The ion product of water = 1.0 x 10~14
Part 1 of 2
H3 0+ | in each solution and label the solution as acidic, basic, or neutral.
M
(Choose one)
Be sure your answer has the correct number of significant figures.
H30+=10^-5 M
[он]=
This solution is
Part 2 [H30+]=3.8 x 10-7 M
OH^-=
what is the answer for part 1 and 2
Part 1:
[H3O+] = 10^-5 M
To find [OH-], we can use the ion product of water:
[H3O+][OH-] = 1.0 x 10^-14
10^-5 [OH-] = 1.0 x 10^-14
[OH-] = 1.0 x 10^-14 / 10^-5
[OH-] = 1.0 x 10^-9 M
Since [OH-] > 1.0 x 10^-7 M, this solution is basic.
Answer for Part 1: [OH-] = 1.0 x 10^-9 M, solution is basic.
Part 2:
[H3O+] = 3.8 x 10^-7 M
Using the ion product of water:
[H3O+][OH-] = 1.0 x 10^-14
3.8 x 10^-7 [OH-] = 1.0 x 10^-14
[OH-] = 1.0 x 10^-14 / 3.8 x 10^-7
[OH-] ≈ 2.63 x 10^-8 M
Since [OH-] < 1.0 x 10^-7 M, this solution is acidic.
Answer for Part 2: [OH-] ≈ 2.63 x 10^-8 M, solution is acidic.
I hope this helps! Let me know if you have any further questions.