Consider the functions f (x) = 4x²+ 8x - 10 and g(x) = 5x²+10x - 1
Function f is a graph whose vertex is
(1 point)
O higher than
lower than
located at the same axis of symmetry as
the vertex for the graph of function g.
The vertex for function f can be found using the formula x = -b/2a.
For f(x) = 4x² + 8x - 10, a = 4 and b = 8. So, x = -8/(2*4) = -1.
To find the corresponding y-coordinate, substitute x = -1 into the function:
f(-1) = 4(-1)² + 8(-1) - 10 = 4 - 8 - 10 = -14
Therefore, the vertex for function f is at the point (-1, -14).
Now, we need to determine the vertex for function g. Following the same steps as above, we find that the vertex for function g is at the point (-1, -6).
Comparing the two vertices, we see that they have the same x-coordinate (-1) but different y-coordinates (-14 for f and -6 for g). Therefore, the vertex for function f is lower than the vertex for function g.
The vertex for the graph of function f is
(1 point)
O2 units to the right of
2 units to the left of
O located at the same axis of symmetry as
the vertex for the graph of function g.
To find the vertex of function f, we need to use the formula x = -b/2a.
For f(x) = 4x² + 8x - 10, a = 4 and b = 8. So, x = -8/(2*4) = -1.
Now, substitute x = -1 back into the equation f(x) to find the corresponding y-coordinate:
f(-1) = 4(-1)² + 8(-1) - 10 = 4 - 8 - 10 = -14.
So, the vertex for function f is at the point (-1, -14).
The vertex for function g has already been determined to be at the point (-1, -6).
Comparing the x-coordinates of the two vertices, we see that they have the same x-coordinate (-1). Therefore, the vertex for function f is located at the same axis of symmetry as the vertex for function g.