A badminton player hits a shuttlecock towards her opponent. For a short part of its trajectory (Δx=1,074 m
), the shuttlecock moves in an approximately straight line over a period of Δt=0,02 s
. The shuttlecock has a mass of m=5 g
.
Ignore the effects of air resistance. Also ignore the effects of gravity on the shuttlecock during this short part of its trajectory.
Calculate the magnitude of the average velocity (vavg
) of the shuttlecock over this period of its trajectory.
To calculate the magnitude of the average velocity of the shuttlecock, we can use the formula:
Average velocity = displacement / time
Given:
Displacement (Δx) = 1,074 m
Time (Δt) = 0.02 s
Average velocity = 1,074 m / 0.02 s
Average velocity = 53,700 m/s
Therefore, the magnitude of the average velocity of the shuttlecock over this period of its trajectory is 53,700 m/s.