Solve the system of two equations using substitution.
y=2+3x4x−3y=−16(1 point)Responses(2, 8)left parenthesis 2 comma 8 right parenthesis(−2, −4) left parenthesis negative 2 comma negative 4 right parenthesis(−2, 4) left parenthesis negative 2 comma 4 right parenthesis(2, 10)
First, we'll use the first equation to solve for y in terms of x:
y = 2 + 3x
Now we substitute this expression for y into the second equation:
4x - 3(2 + 3x) = -16
4x - 6 - 9x = -16
-5x - 6 = -16
-5x = -10
x = 2
Now that we have the value of x, we can substitute it back into the first equation to solve for y:
y = 2 + 3(2)
y = 2 + 6
y = 8
Therefore, the solution to the system of equations is (2, 8).