In a certain game, a ball is randomly selected from a box that contains 3 red balls, 2 green balls and 6 blue balls. If a red ball is selected R5 is won, if green you win R4 and if blue is selected you win nothing. Suppose that two balls are selected at random with replacement, what is the probability of wining R8.
To win R8, the two balls selected must both be green.
The probability of selecting a green ball on the first draw is 2/11.
Since the balls are replaced after each draw, the probability of selecting a green ball on the second draw is also 2/11.
Therefore, the probability of selecting two green balls in a row and winning R8 is (2/11) * (2/11) = 4/121.
Therefore, the probability of winning R8 is 4/121.