A balanced coin is tossed 3 times. Let A = {a head is obtained} and B = {a tail is obtained}. Calculate the probability to get two heads
When a balanced coin is tossed, there are two possible outcomes - head (H) or tail (T) with each outcome having a probability of 0.5.
Let's consider the event of getting two heads (HH) when the coin is tossed 3 times.
The probability of getting a head on each toss is 0.5, so the probability of getting two heads (HH) in three tosses can be calculated as follows:
P(HH) = P(H on first toss) * P(H on second toss) * P(T on third toss)
P(HH) = 0.5 * 0.5 * 0.5 = 0.125
Therefore, the probability of getting two heads when a balanced coin is tossed 3 times is 0.125 or 12.5%.