A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = –16t² + 60t + 6. What will the height be at t = 3 seconds?
Possible Answers:
35 Feet
40 Feet
42 Feet
45 Feet
To find the height at t = 3 seconds, we need to substitute t = 3 into the equation h = -16t^2 + 60t + 6:
h = -16(3)^2 + 60(3) + 6
h = -16(9) + 180 + 6
h = -144 + 180 + 6
h = 42
Therefore, the height at t = 3 seconds is 42 feet. The answer is 42 Feet.