Use the equation below to calculate the answer.
W = (F) x (d)
A professional baseball player runs 21m from centerfield to try and rob a homerun. The baseball player collides with the wall and makes catch 122m away from Homeplate. The player exerts a force of 900N on the wall as he hits it. The wall is flexible and initially bends back by about 0.2m upon collision. However, the wall ultimately snaps back into its original position and is NOT displaced at all. How much work did the player do to the wall?
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1 point
180J
0J
18,900J
109,800J
The work done by the player can be calculated using the equation provided:
W = (F) x (d)
Where:
W = work done
F = force applied (900N)
d = displacement (0.2m)
W = 900N x 0.2m
W = 180J
Therefore, the work done by the player to the wall is 180J. The correct answer is:
180J
how do you know if this is right?
To ensure that the calculation is correct, we need to check if the work done is positive or negative. Work done by a force is considered positive if the force is in the same direction as the displacement and negative if the force is in the opposite direction of the displacement.
In this case, the force of 900N is applied in the direction of the displacement (since the wall initially bends back), so the work done should be positive.
Therefore, the calculation provided is correct. The player did 180J of work on the wall.
Use the equation below to calculate the answer.
W = (F) x (d)
Jeremy kicks a soccer ball with a force of 250N. Jeremy got a running start and was 2m away from the ball before he made contact. The ball traveled 25m and hit a mailbox with a force of 200N. The mailbox does not move at all, but the ball rolls backwards 3m in the direction of Jeremy. What was the work done by Jeremy to the soccer ball?
*Hint when finding the final distance between Jeremy and the ball to plugin to the equation above, remember that the ball rolled backwards a certain distance after hitting the mailbox.
*
1 point
6250J
600J
0J
5500J
First, let's calculate the work done by Jeremy on the soccer ball.
Given:
Initial distance between Jeremy and the ball (d1) = 2m
Force applied by Jeremy (F) = 250N
To find the total work done by Jeremy on the soccer ball, we need to calculate the work done when Jeremy kicks the ball and when the ball hits the mailbox.
Work done when Jeremy kicks the ball:
d1 = 2m
W1 = F x d1
W1 = 250N x 2m
W1 = 500J
Work done when the ball hits the mailbox:
Since the ball rolls backward 3m after hitting the mailbox, the final distance between Jeremy and the ball (d2) will be 2m (initial) + 25m (distance traveled) - 3m (rolled back) = 24m.
d2 = 24m
Force applied by the mailbox (F) = 200N
W2 = F x d2
W2 = 200N x 24m
W2 = 4800J
Total work done = W1 + W2
Total work done = 500J + 4800J
Total work done = 5300J
Therefore, the work done by Jeremy to the soccer ball is 5300J. So, the correct answer is:
5500J