A spinner has 3 different colors: blue, red and green. If the probability of getting blue is ⅓, the probability of getting red is ¼. If the spinner has 12 sections, how many green sections are there?
Let x be the number of green sections on the spinner.
Since the total number of sections on the spinner is 12, the probability of getting green is x/12.
We are given that the probability of getting blue is 1/3 and the probability of getting red is 1/4.
Therefore, the total probability from all three colors should be 1:
1/3 (blue) + 1/4 (red) + x/12 (green) = 1
Multiplying through by 12 to eliminate fractions:
4 + 3 + x = 12
7 + x = 12
x = 12 - 7
x = 5
Therefore, there are 5 green sections on the spinner.