How many real number solutions are there to the equation 0 = –3x² + x – 4?
To find the number of real number solutions to the equation 0 = –3x² + x – 4, we need to determine the discriminant of the quadratic equation.
The discriminant is calculated as b^2 - 4ac, where a = -3, b = 1, and c = -4.
Plugging in these values, we get:
Discriminant = (1)^2 - 4(-3)(-4)
Discriminant = 1 - 48
Discriminant = -47
Since the discriminant is negative (-47), there are no real number solutions to the equation 0 = –3x² + x – 4.