Write y −2= 3/2 (x+2) in slope-intercept form.(1 point)
y = (3/2)x + 7
plz try again
y - 2 = 3/2(x + 2)
y - 2 = 3/2x + 3
y = 3/2x + 3 + 2
y = 3/2x + 5
Therefore, the equation in slope-intercept form is y = 3/2x + 5.
Graph the equation 9−x=3/2y using slope-intercept form.(1 point)
To graph the equation 9 - x = 3/2y in slope-intercept form, we need to first isolate y:
9 - x = 3/2y
3/2y = 9 - x
y = 2/3(9 - x)
Now let's write this equation in slope-intercept form:
y = 2/3(9) - 2/3x
y = 6 - 2/3x
The slope-intercept form of the equation is y = -2/3x + 6.
Now let's graph this equation:
- Plot the y-intercept at y=6.
- Using the slope -2/3, means we go down 2 units and move to the right 3 units for every step.
Drawing the graph, it would look like this:
Graph:
```
|
6 +------------------------
|
|
|
|
|
----------
3
```
This represents the graph of the linear equation y = -2/3x + 6.