Use the formula for the volume of a rectangular pyramid to find the volume of a pyramid-shaped tent whose height is 75 in., width is 111 in., and length is 111 in. when standing.(1 point) Responses 400,000 in.3 400,000 in. cubed 924,075 in.3 924,075 in. cubed 33,034.03 in.3 33,034.03 in. cubed 308,025 in.3 308,025 in. cubed
The formula for the volume of a rectangular pyramid is: V = (1/3) x length x width x height
Given:
height = 75 in
width = 111 in
length = 111 in
V = (1/3) x 111 x 111 x 75
V = (1/3) x 111 x 111 x 75
V = (1/3) x 1,110,375
V = 370,125 in^3
Therefore, the volume of the pyramid-shaped tent is 370,125 in^3.
answers are: 400,000 in.3 400,000 in. cubed 924,075 in.3 924,075 in. cubed 33,034.03 in.3 33,034.03 in. cubed 308,025 in.3 308,025 in. cubed
Apologies for the mistake in the calculation. Let's correct it:
Given:
height = 75 in
width = 111 in
length = 111 in
V = (1/3) x length x width x height
V = (1/3) x 111 x 111 x 75
V = (1/3) x 999,375
V = 333,125 in^3
Therefore, the volume of the pyramid-shaped tent is 333,125 in^3.
So, the closest answer is 308,025 in^3.