A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land? Round your answer to the nearest hundredth. (1 point) Responses
4.30 m
160.56 m
161.12 m
13.94 m
We need to find the value of x when y = 0.
The equation provided in the problem is missing, but assuming that the equation follows a typical projectile motion equation, it could be something like:
y = -0.5g*t^2 + v0*t + h0
Where:
- y is the height of the rocket
- g is the acceleration due to gravity (approx. 9.8 m/s^2)
- t is the time
- v0 is the initial vertical velocity (0 m/s if launched horizontally from a roof)
- h0 is the initial height above the ground (height of the roof)
Setting y = 0, we find:
0 = -0.5g*t^2 + h0
This gives us the time it takes for the rocket to hit the ground. Then, we can find x using the equation:
x = v0*t
Please provide the complete equation if it's different from the typical projectile motion equation given above.