How many grams of oxygen are there in 89.6l of oxygen at S.T.P
At standard temperature and pressure (S.T.P), the volume of 1 mole of gas is 22.4 liters. So, to find the number of moles of oxygen in 89.6 liters, we divide 89.6 by 22.4:
89.6/22.4 = 4 moles
Since the molar mass of oxygen is 32 g/mol, we can now find the total grams of oxygen in 89.6 liters:
4 moles * 32 g/mol = 128 grams
Therefore, there are 128 grams of oxygen in 89.6 liters of oxygen at S.T.P.