A big stone of mass 1000g, is projected at an angle of 30 degree from the ground it cover a maximum vertical distance of 5m, acceleration due to gravity is 10m/s square, what is the velocity with which it was thrown?
Given:
Mass of stone (m) = 1000g = 1kg
Angle of projection (θ) = 30 degrees
Maximum vertical distance (y) = 5m
Acceleration due to gravity (g) = 10 m/s^2
The maximum vertical distance covered by the stone can be calculated using the formula:
y = (u^2sin^2(θ))/(2g)
Solving for initial velocity (u):
5 = (u^2sin^2(30))/(2*10)
5 = (u^2*(1/4))/(20)
5 = u^2/80
u^2 = 400
u = 20 m/s
Therefore, the velocity with which the stone was thrown is 20 m/s.