What volume would 9.41 x 10²⁶ molecules of N₂ occupy?
To find the volume occupied by 9.41 x 10²⁶ molecules of N₂, we first need to determine the amount of gas in moles, then use the ideal gas law to calculate the volume.
1. Calculate the moles of N₂:
1 mole of any gas contains 6.022 x 10²³ molecules.
So, 9.41 x 10²⁶ molecules of N₂ is equal to:
9.41 x 10²⁶ / 6.022 x 10²³ = 1.565 moles of N₂
2. Use the ideal gas law formula to calculate the volume:
PV = nRT
Where:
P = pressure
V = volume
n = moles
R = gas constant (0.0821 L atm/mol K)
T = temperature
Assuming standard conditions (1 atm and 298 K), the formula becomes:
V = nRT / P
V = (1.565 mol)(0.0821 L atm/mol K)(298 K) / 1 atm
V = 38.82 L
Therefore, 9.41 x 10²⁶ molecules of N₂ would occupy a volume of 38.82 liters.