What weight of NaOH would be required to prepare 3000 ml of a 2.5M solution?
each liter of a 2.5M solution requires 2.5M, so you need 7.5mole
Isn't it 40 grams per mole for NaOH? check that.
300 grams
To calculate the weight of NaOH required to prepare a certain volume of a specific concentration solution, you need to use the formula:
Weight = Volume (in liters) x Concentration (in moles/liter) x Molecular Weight
In this case, you have:
Volume = 3000 ml = 3000 / 1000 = 3 liters (converted to liters)
Concentration = 2.5 M (Molar concentration)
To find the molecular weight (MW) of NaOH:
Na (Sodium) = 22.99 g/mol
O (Oxygen) = 16.00 g/mol
H (Hydrogen) = 1.01 g/mol
So, the molecular weight of NaOH = 22.99 + 16.00 + 1.01 = 40.00 g/mol
Now, let's calculate the weight of NaOH:
Weight = 3 liters x 2.5 moles/liter x 40.00 g/mol
Weight = 3 x 2.5 x 40.00 = 300 grams
Therefore, to prepare a 2.5M NaOH solution with a volume of 3000 ml, you would need 300 grams of NaOH.