Calculate the molarity of each aqueous solution with the given amount of C6H1206 (molar mass 180.15
entries has the correct number of significant figures.
Note: Reference the SI prefixes table for additional information.
Part 1 of 3
10
1.50 mol C6H1206 in 0.430 L solution
M
olarity = moles of solute / liters of solution
Molarity = 1.50 mol / 0.430 L = 3.49 M
Therefore, the molarity of the solution is 3.49 M.