A medical lab is testing a new anticancer drug on cancer cells. The drug stock solution concentration is 1.5×10−9M
, and 5.00 mL
of this solution will be delivered to a dish containing 2.0×105
cancer cells in 5.00 mL
of aqueous fluid.
To calculate the final concentration of the anticancer drug in the dish, we need to determine how many moles of the drug are present in the stock solution and then calculate the final volume of the solution in the dish.
1. Calculate the number of moles of the drug in the stock solution:
Molarity (M) = moles of solute / liters of solution
moles of solute = Molarity x volume of solution (in liters)
moles of solute = 1.5 x 10^-9 mol/L x (5.00 x 10^-3 L) = 7.5 x 10^-12 moles
2. Determine the final volume of the solution in the dish:
The final volume will be the sum of the volumes of the drug stock solution and the aqueous fluid in the dish:
Final volume = 5.00 mL + 5.00 mL = 10.00 mL = 10.00 x 10^-3 L
3. Calculate the final concentration of the drug in the dish:
Final concentration = moles of solute / final volume of solution
Final concentration = 7.5 x 10^-12 moles / 10.00 x 10^-3 L = 7.5 x 10^-10 M
Therefore, the final concentration of the anticancer drug in the dish containing 2.0 x 10^5 cancer cells in 5.00 mL of aqueous fluid would be 7.5 x 10^-10 M.