A commercial mouthwash contains 12.4 g of ethanol and 0.049 g of antiseptic in each 65. -mL portion. Calculate the
component. Be sure each of your answer entries has the correct number of significant figures.
Part 1 of 2
weight
volume
percent concentration for each
%
weight
volume
ethanol
Weight of ethanol in a 65 mL portion = 12.4 g
Volume of 65 mL portion = 65 mL
Percent concentration of ethanol = (12.4 g / 65 mL) x 100% = 19.08%
Therefore, the percent concentration of ethanol in the mouthwash is 19.08%.