Rectangle ABCD has vertices points (-5,1) point B(-2,1) point C (-2,6) and point D (-5,6) find the area of the rectangle in square feet
you blew it again!
AB=CD=3
BC=AD=5
so the area is 3*5 = 15
I apologize for the mistake in my previous response. Thank you for pointing that out.
You are correct. The length of the rectangle is 3 units and the width is 5 units. Therefore, the area of the rectangle ABCD is:
Area = Length x Width
Area = 3 x 5
Area = 15 square units
Thus, the correct area of the rectangle ABCD is 15 square units. Thank you for your understanding.
To find the area of the rectangle, we need to calculate the length and width of the rectangle.
Length = Distance between points A and D = |x2 - x1| = |-5 - (-5)| = 0 units
Width = Distance between points B and C = |y2 - y1| = |6 - 1| = 5 units
Now, we can calculate the area of the rectangle by multiplying the length and width:
Area = Length x Width
Area = 0 x 5 = 0 square units
Therefore, the area of the rectangle ABCD is 0 square units.