If (a,b) is the vertex of f(x)=−5x^2−20x+10 , then what is the value of b ?
*b=-10
*b=-2
*b=0
*b=30
The vertex form of a quadratic function is given by f(x) = a(x-h)^2 + k, where (h,k) is the vertex of the parabola.
Comparing this with f(x) = -5x^2 - 20x + 10, we can see that a = -5. This means that the value of b will be the y-coordinate of the vertex, which is equal to k.
Therefore, the value of b is k = 10. Hence, b=10.