The coordinates (3,−1) , (1,−3) , and (5,−3) were plotted to draw a triangle on a coordinate plane. Is the polygon in Quadrant I, II, III, or IV? Answer 1 for Quadrant I, 2 for Quadrant II, 3 for Quadrant III, or 4 for Quadrant IV. (1 point)
Quadrant
no its 4
II
Apologies for the mistake. The correct answer is 4 for Quadrant IV. Thank you for pointing that out.
Given the coordinates (7,−3) , (7,−8) , (11,−4) , and (11,−9) , what is the length of the vertical sides of the quadrilateral, in cm?(1 point)
cm
To find the length of the vertical sides of the quadrilateral, we need to calculate the difference in the y-coordinates between each pair of points that make up the vertical sides.
- The vertical side with coordinates (7,−3) and (7,−8) has a length of |−8 - (-3)| = 5 cm.
- The vertical side with coordinates (11,−4) and (11,−9) has a length of |−9 - (-4)| = 5 cm.
Therefore, the length of the vertical sides of the quadrilateral is 5 cm.
Given the coordinates (9,−2) , (9,−11) , (15,−4) , and (15,−13) , what is the length of each of the two longest sides of the quadrilateral, in cm?(1 point)
cm
To find the length of the two longest sides of the quadrilateral, we need to determine the distances between the pairs of points that create those sides.
The two longest sides are the sides with the points (9, -11) and (15, -13) and the points (9, -2) and (15, -4).
1. The length of the side with coordinates (9, -11) and (15, -13) can be found as follows:
Distance = sqrt((15-9)^2 + (-13 - (-11))^2)
= sqrt(6^2 + (-2)^2)
= sqrt(36 + 4)
= sqrt(40)
= 2√10
≈ 6.32 cm
2. The length of the side with coordinates (9, -2) and (15, -4) can be found as follows:
Distance = sqrt((15-9)^2 + (-4 - (-2))^2)
= sqrt(6^2 + (-2)^2)
= sqrt(36 + 4)
= sqrt(40)
= 2√10
≈ 6.32 cm
Therefore, the length of each of the two longest sides of the quadrilateral is approximately 6.32 cm.