Joseph has a rain barrel in the shape of a cylinder with a height of 48 inches and a diameter of 24 inches. What is the surface area of the rain barrel? Use 3.14 for π and round to the nearest tenth
To find the surface area of the rain barrel, we first need to find the total surface area of the cylinder which includes the top and bottom circles, as well as the side surface.
Surface area of the top and bottom circles:
A = 2πr^2
A = 2 * 3.14 * (12 inches)^2
A = 2 * 3.14 * 144
A = 2 * 452.16
A = 904.32 square inches
Surface area of the side surface:
A = 2πrh
A = 2 * 3.14 * 12 inches * 48 inches
A = 3.14 * 576 inches
A = 1808.64 square inches
Total surface area of the rain barrel:
Total A = 904.32 + 1808.64
Total A = 2712.96 square inches
Therefore, the surface area of the rain barrel is approximately 2712.96 square inches.