Mrs. Amrhein made a cylindrical can. It has a height of 5 in and a diameter of 3 in. How much material does she need to wrap the can with no over lap?
TOTAL Surface Area
Mrs. Amrhein made a cylindrical can. It has a height of 5 in and a diameter of 3 in. How much material does she need to wrap the can with no over lap?
TOTAL Surface Area
To find the total surface area of the cylindrical can, we need to calculate the lateral surface area and the area of the two circular bases.
The lateral surface area of a cylinder is given by the formula: 2πrh, where r is the radius and h is the height. Since the diameter is 3 in, the radius (r) is half of that, which is 1.5 in.
So, the lateral surface area = 2π(1.5)(5) = 15π in^2.
The area of one circular base is given by the formula: πr^2.
So, the total area of the two circular bases = 2(π(1.5)^2) = 4.5π in^2.
Therefore, the total surface area of the cylindrical can = 15π + 4.5π = 19.5π in^2.
Approximately, the total surface area is 61.3 in^2.
Mrs. Amrhein needs approximately 61.3 square inches of material to wrap the can with no overlap.