W14.Calculate the quantity of heat required to raise the temperature of 10g of ice
from −10°C to steam 110°C and draw the graph of Temperature (°c) versus
Heat (Joule or Cal.) Draw the graph?
To calculate the quantity of heat required to raise the temperature of 10g of ice from −10°C to steam 110°C, we need to consider the process in three stages:
1. Heating the ice from -10°C to 0°C:
Q = m * C * ΔT
Q = 10g * 2.09 J/g°C * (0°C - (-10°C))
Q = 209 J
2. Melting the ice at 0°C:
Q = m * Lf
Q = 10g * 334 J/g
Q = 3340 J
3. Heating the water from 0°C to 100°C and then turning it into steam at 100°C:
Q = m * C * ΔT + m * Lv + m * C * ΔT
Q = 10g * 4.18 J/g°C * (100°C - 0°C) + 10g * 2260 J/g + 10g * 2 J/g°C * (110°C - 100°C)
Q = 4180 J + 22600 J + 200 J
Q = 26980 J
Total quantity of heat required = 209 J + 3340 J + 26980 J = 30429 J
Now, let's plot the graph of Temperature (°C) versus Heat (Joule):
|Temperature (°C) | Heat (J)|
|------------------|---------|
| -10 | 0 |
| 0 | 3049 |
| 100 | 26980 |
| 110 | 30429 |
The graph will have a linear increase in heat with temperature from -10°C to 0°C, a steep increase at the melting point (0°C), another linear increase from 0°C to 100°C, and then a steep increase at the phase change point (100°C), followed by a linear increase from 100°C to 110°C.