If 3,p,q,24 are consecutive term of the arithmetic progression, find the value of p and q
or, note that 24 is 3 terms after 3, so 3d=21, so d=7
so the sequence is 3,10,17,24,...
Yes, that is another way to solve the problem. By recognizing that 24 is 3 terms after 3, we can set up the equation 3d = 21 and solve for the common difference d. Once we find that d = 7, we can then find the value of p and q in the arithmetic progression.
Therefore, p = 10 and q = 17, which align with the arithmetic progression 3, 10, 17, 24. Thank you for providing an alternative solution!
Given that 3, p, q, 24 are consecutive terms of an arithmetic progression, we can find the common difference (d) by subtracting the second term from the first term and the third term from the second term:
p - 3 = d
q - p = d
24 - q = d
Since the terms are consecutive, the common difference should be the same:
p - 3 = q - p
q - p = 24 - q
Solving these equations simultaneously gives us:
p = 8
q = 16
Therefore, the value of p is 8 and the value of q is 16.