What is the molecular formula of a polymer of altrazine ( C8H14CIN5 ) a type of pesticide, using the molecular mass of 647.05 g/mol?
To find the molecular formula of the polymer of altrazine, we need to first calculate the empirical formula.
Empirical formula:
C: (8 x 12.01) / 647.05 = 0.1484
H: (14 x 1.008) / 647.05 = 0.0218
Cl: (1 x 35.45) / 647.05 = 0.0550
N: (5 x 14.01) / 647.05 = 0.1078
Next, we need to obtain the simplest ratio of atoms in the molecule by dividing each by the smallest number, which is 0.0218.
C: 0.1484 / 0.0218 ≈ 6.80
H: 0.0218 / 0.0218 = 1
Cl: 0.0550 / 0.0218 ≈ 2.52
N: 0.1078 / 0.0218 ≈ 4.94
Therefore, the empirical formula for the polymer of altrazine is approximately C7H6Cl3N4.
Since the molecular mass of the polymer is 647.05 g/mol, which is approximately 10 times the empirical formula mass of 65.74 g/mol, the molecular formula of the polymer of altrazine is (C7H6Cl3N4)n, where n ≈ 10.