Evaluateh(x)=3−2x−12whenx=−3.
a.h(−3)=−15
b.h(−3)=−4
c.h(−3)=−3
d.h(−3)=−14
To evaluate h(x) when x = -3, we substitute -3 in for x in the function:
h(-3) = 3 - 2(-3) - 12
h(-3) = 3 + 6 - 12
h(-3) = 9 - 12
h(-3) = -3
Therefore, the correct answer is c. h(-3) = -3.