A sample with a mass of 3.698 g consists of 64.93% tin and 35.07% sulfur. What is the molar ratio of sulfur to tin in the sample?
To find the molar ratio of sulfur to tin in the sample, we first need to convert the masses of tin and sulfur into moles using their respective molar masses.
Molar mass of tin (Sn) = 118.71 g/mol
Molar mass of sulfur (S) = 32.06 g/mol
Mass of tin in the sample = 3.698 g x 0.6493 = 2.399 g
Mass of sulfur in the sample = 3.698 g x 0.3507 = 1.299 g
Number of moles of tin = 2.399 g / 118.71 g/mol = 0.0202 mol
Number of moles of sulfur = 1.299 g / 32.06 g/mol = 0.0406 mol
Therefore, the molar ratio of sulfur to tin in the sample is approximately 0.0406 mol : 0.0202 mol, which simplifies to 2:1.
So, the molar ratio of sulfur to tin in the sample is 2:1.