Solve the system of equations. x=6y−3 and 2x+7y=13(1 point) (, )
To solve the system of equations, we need to substitute the value of x from the first equation into the second equation.
Given:
x = 6y - 3
2x + 7y = 13
Substitute x into the second equation:
2(6y - 3) + 7y = 13
12y - 6 + 7y = 13
19y - 6 = 13
19y = 19
y = 1
Now, substitute y back into the first equation to find the value of x:
x = 6(1) - 3
x = 6 - 3
x = 3
Therefore, the solution to the system of equations is x = 3 and y = 1. So, the ordered pair is (3, 1).