The coil rotates a further 90°. What will the induced emf be at that point?
The induced emf at any point on a coil rotating in a magnetic field is given by the formula:
ε = N * B * A * ω * sin(θ)
Where:
ε = induced emf
N = number of turns in the coil
B = magnetic field strength
A = area of the coil
ω = angular velocity of the coil
θ = angle by which the coil has rotated
If the coil rotates a further 90°, then the new angle of rotation would be 90°. Plugging this into the formula, the induced emf at that point would be:
ε = N * B * A * ω * sin(90°) = N * B * A * ω * 1 = N * B * A * ω
So the induced emf at that point would be N * B * A * ω.