Suppose a spherical asteroid has a radius of approximately 3.2 × 10^3 m. Use the formula 4/3 r^3 to find the approximate volume of the asteroid.
V ≈ (4/3)π(3.2 × 10^3)^3
V ≈ (4/3)π(32,000)^3
V ≈ (4/3)π(32,000)(32,000)(32,000)
V ≈ (4/3)π(32,000)(1,024,000,000)
V ≈ (4/3)π(32,768,000,000)
V ≈ (4/3)π(103,686,860,416)
V ≈ (4/3)(103,686,860,416)π
V ≈ 138,248,480,555.2 m^3
Therefore, the approximate volume of the asteroid is 138,248,480,555.2 cubic meters.