Solve the system of two equations using substitution y = 2 + 3x and 4x - 3y = -16 a 2, 8 B - 2, 4 C 2, 10 D -2,-4
First, substitute the first equation into the second equation:
4x - 3(2 + 3x) = -16
4x - 6 - 9x = -16
-5x - 6 = -16
-5x = -10
x = 2
Once you have found x, substitute it back into the first equation to solve for y:
y = 2 + 3(2)
y = 2 + 6
y = 8
Therefore, the solution to the system of equations is x = 2 and y = 8, giving you answer A: 2,8.