Polynomials
Solve the following in box method:
3 to the second power times 16x minus 18 equals negative 6
Here is the solution using the box method:
\[
\begin{array}{|c|c|}
\hline
3x^2 & 16x \\
-18 & -6 \\
\hline
\end{array}
\]
Now, we will fill in the boxes:
\[
\begin{array}{|c|c|}
\hline
3x^2 & 16x \\
-18 & -6 \\
\hline
-54x^2 & -288x \\
36 & 12 \\
\hline
\end{array}
\]
So, the simplified equation is \[ 3x^2 \times 16x - 18 = -6 \] which simplifies to \[ -54x^2 - 288x + 36x + 12 = 0 \]
\[ -54x^2 - 252x + 12 = 0 \]