Draw a free body diagram of the forces acting on the helium balloon in three different scenarios. Label the forces and write the values of the gravitational force, the buoyant force (lift), and the net force. Scenario 1: Helium balloon lifting off the ground Scenario 2: Helium balloon hovering midairScenario 3: Helium balloon landing
While the procedure aimed to achieve equilibrium to make the balloon stay still in one spot, it could still move side to side because of things like wind, turbulence, not being perfectly balanced, and changes in the weather.
4. In the equilibrium position, what is the net force acting on the balloon? Explain why.
In Scenario 1:
Forces acting on the helium balloon:
1. Gravitational force (mg) - pointing downwards
2. Buoyant force (lift) - pointing upwards
3. Net force - upwards
Gravitational force = mass x acceleration due to gravity
Buoyant force = weight of the displaced air
In Scenario 2:
Forces acting on the helium balloon:
1. Gravitational force (mg) - pointing downwards
2. Buoyant force (lift) - pointing upwards
3. Net force - 0 (in equilibrium)
In Scenario 3:
Forces acting on the helium balloon:
1. Gravitational force (mg) - pointing downwards
2. Buoyant force (lift) - pointing upwards
3. Net force - downwards (during landing process)
In the equilibrium position, the net force acting on the balloon is zero. This is because the buoyant force (lift) is equal in magnitude but opposite in direction to the gravitational force, resulting in a balanced force system. This balance allows the helium balloon to stay still in one spot.